2w^2+9w-893=0

Solution for 2w^2+9w-893=0 equation:

2w^2+9w-893=0

a = 2; b = 9; c = -893;
Δ = b2-4ac
Δ = 92-4·2·(-893)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-85}{2*2}=\frac{-94}{4}
=-23+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+85}{2*2}=\frac{76}{4}
=19
$